用set进行,加上一个小优化,就可以算最近点对,没有特别的数据1
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using namespace std;
ll x[maxn],y[maxn];
struct node
{
ll x,y;
bool operator < (const node &u) const{
if(x == u.x) return y < u.y;
return x < u.x;
}
};
int main()
{
int t;
ll n,Ax,Ay,Bx,By,Cx,Cy;
scanf("%d", &t);
while (t--){
set<node> st;
st.clear();
cin>>n>>Ax>>Bx>>Cx>>Ay>>By>>Cy;
//cout<<n<<' '<<Ax<<' '<<Cy<<endl;
//scanf("%I64d%I64d%I64d%I64d%I64d%I64d%I64d", &n, &Ax, &Bx, &Cx, &Ay, &By, &Cy);
x[0] = 0; y[0] = 0;
for (int i = 1; i <= n; ++i){
x[i] = (x[i-1]*Ax + Bx) % Cx;
y[i] = (y[i-1]*Ay + By) % Cy;
}
ll sum = 0;
node tmp;
tmp.x = 0; tmp.y =0;
//st.insert(tmp);
tmp.x = x[1]; tmp.y= y[1];
st.insert(tmp);
ll ans = 1e17;
//cout << ans << endl;
for (ll i = 2; i <= n; ++i)
{
tmp.x = x[i]; tmp.y = y[i];
set<node>::iterator it,ii;
it = st.lower_bound(tmp);
for (ii = it; ii != st.end(); ++ii)
{
if((ii->x-tmp.x) * (ii->x-tmp.x) >= ans) break;
ll dis = (ii->x-tmp.x) * (ii->x-tmp.x) + (ii->y-tmp.y) * (ii->y-tmp.y) ;
ans = min(ans,dis);
}
ii = it;
while (ii != st.begin())
{
ii --;
if((ii->x-tmp.x) * (ii->x-tmp.x) >= ans) break;
ll dis = (ii->x-tmp.x) * (ii->x-tmp.x) + (ii->y-tmp.y) * (ii->y-tmp.y) ;
ans = min(ans,dis);
}
sum += ans;
st.insert(tmp);
}
//printf("%I64dn",sum);
cout << sum << endl;
}
return 0;
}
HDU 4631 Sad Love Story (2013 多校第三场 K)
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